$3x-7>4$
$\tan^2\left(x\right)-3\sin\left(x\right)\tan\left(x\right)\sec\left(x\right)$
$\left(a+8\right)\left(b+3\right)$
$\int3x\sin^2\left(x\right)dx$
$\frac{cosx}{sinxcotx}=1$
$-5\left(-1+7x\right)-7\left(1+8r\right)$
$\frac{3x^3-10x^2+2}{x^2-2x}$
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