$.005+.4+.03$
$\left(8x+3x-y\right)^2$
$3x\:-\:1\:\le\:4x$
$10x^2-x-3$
$-\frac{x^3}{3}+x^2+8x;\:x=-2;\:y=0$
$\lim_{x\to\infty}\frac{\left(\tan\left(2x\right)cos\left(2x\right)-sin\left(5x\right)\right)}{sin\left(3x\right)}$
$\left(z^2-3z+3\right)-2\left(z-1\right)$
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