$\int\left(-16x^3\left(-4x^4-1\right)^{-5}\right)dx$
$100\left(15x\right)$
$\left(x+\frac{1}{2}m\right)\left(x-\frac{3}{2}m\right)$
$-14-x=20$
$\lim_{x\to0}\left(\frac{x^3}{x^2+x\:}\right)$
$16^x\:=\:64^{x+4}\:$
$\frac{dy\left(t\right)}{dt}+y\left(t\right)=\sin\left(t\right)$
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