$3x^2-5x+6\cdot4x-2$

$cos\left(t\right)\left(\frac{sin\left(h\right)}{h}\right)+sin\left(t\right)\left(\frac{cos\left(h\right)-1}{h}\right)$

$\:-6x\:+\:3;\:x=\:-2$

$3x-2=5x+6$

$\int\frac{1}{\left(x^2+4\left(3+x\right)-3x\right)}dx$

$\frac{x^2+y^2-2xy}{\left(x+y\right)\left(x-y\right)}$

$-6\:+9\:+4\:+\:-2\:-6\:-9\:-\:-3\:-5\:-6$