$\left(x^3+3\right)^4$
$x''+16x=0$
$\left(x-15\right)\left(x-25\right)$
$\frac{\frac{x}{1+x}}{x^3}$
$3y+2x+4^2$
$\left(-x^2y\right)^3\left(x^3y^{-1}\right)^2$
$\left(y^{-1}+x^3\right)\left(y^{-1}-x^3\right)$
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