$\frac{x^2\sin^3\left(90\right)+y^2\cos^5\left(180\right)}{x\sin\left(90\right)+y\cos\left(0\right)}$

$9+4x+x=14$

$\int2\left(x^3+6x\right)^6\left(6x^2+12\right)dx$

$9y\:+\:3$

$\frac{x^4}{81}-\frac{25}{49}$

$\int\frac{4x^2+9}{x^2}dx$

$m\left(x+1\right)^2+\left(x+1\right)-y\left(x+1\right)$