$5^2\cdot5^7\cdot5^{-3}$
$\frac{x^3}{x^2+4}$
$\left(x\cdot4\right)^2$
$3^3x\:3^5:\:3^2$
$9x+9>3x+5$
$2x+4y+z=13$
$\frac{d}{dx}\:\:\:\sqrt[3]{16x^{-8}}$
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