$\left(3x-1\right)^2-\left(4x+1\right)^2$
$\left(6x+12\right)\left(6x-18\right)$
$-\tan\left(x\right)\cot\left(x\right)^2$
$ln\left(\frac{y'}{y}\right)$
$x^2dy-\frac{1}{y}dx=0$
$\left(\sqrt[3]{8}+\sqrt{5}\right)^2+\left(\sqrt[3]{8}-\sqrt{5}\right)^2$
$405b=\left(a+b\right)^2$
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