$2x-6+5x-5->-4$
$\frac{sin^2x+8sinx+16}{sinxcosc+4cosx}$
$16x^4y^2\left(9x^3y^4\right)$
$-x^2-3x+10>10$
$-17\:.\:26$
$4x^2-7x+7$
$\frac{d}{dx}6x^2-3y^5=2x^3y$
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