$\int5x\tan\left(4x^{2}-1\right)dx$
$\sqrt[3]{\frac{x}{y^2}}$
$\left(a+6\right)\left(a-4\right)$
$\int_{-2}^3\left(\frac{16}{x^4}\right)dx$
$8x-16$
$\left(6x^3-x^2\right)\cdot\left(x^2+6x^3\right)$
$\left(2x^4y+4m\right)^3$
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