$3\sin^2\left(x\right)=\sin\left(x\right)$

$\left(11x\:+\:3y\right)\left(11x\:-\:3y\right)\:$

$\frac{\left(3\left(-\frac{1}{3}\right)^3-14\left(-\frac{1}{3}\right)^2-2\left(-\frac{1}{3}\right)+1\right)}{\left(x+\frac{1}{3}\right)}$

$cos\left(x+y\right)$

$-\:\left(-4\right)\:-\:\left(-12\right)\:+\left(-4\right)\:+\:6\:-\:\left(-\:5\right)\:-\:\left(+11\right)\:-\:\left(+3\right)\:+\:9$

$64b^4-36a^2$

$\lim_{x\to3}\left(\frac{3x-x^2}{\left|2x-6\right|}\right)$