$8+5-7+3\left(-4+3\right)$
$\lim_{x\to1}\left(\frac{\ln\left(x\right)}{x^3-3x\:+2}\right)$
$-\frac{1}{5}b-\frac{2}{5}=-2$
$0^4-5\cdot0^2+7\cdot0-20$
$s^2-s-6$
$x^{2}-11x+28$
$16u-5y+3u+7u$
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