$\frac{x+3}{2}+\frac{1}{2x}=\frac{2}{3}$
$2x^4-7x^3-14+8$
$\left(\frac{4}{5}a+\frac{2}{3}b\right)\left(\frac{4}{5}a-\frac{2}{3}b\right)$
$\left(3y\:\sin\left(2x\right)\right)dx-dy=0$
$\frac{\sin\left(x\right)\cos^2\left(x\right)\frac{1}{\sin\left(x\right)}}{\tan^2\left(x\right)}$
$d+8+\frac{c}{2}$
$\int\frac{s^2}{\left(s-1\right)^3\cdot\left(s+1\right)}dx$
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