$\int2x\left(cos\left(3x\right)\right)dx$
$2a^2bc^2;\:a=2;\:b=3;\:c=1$
$a=2,\:b=5,c=3$
$\int\frac{x}{2x^2+2}dx$
$\left(4+x\right)y=y^2$
$\left(4x-3y\right)^2-\left(4x-3y\right)^2$
$\frac{\sqrt{4}}{2}$
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