$\lim_{x\to\infty}\left(\left(1+\frac{x}{2}\right).\frac{1}{x}\right)$

$f\left(x\right)=\frac{x}{\left(1+9x\right)^2}$

$-4\:+5\:+2\:+10\:-11\:+4$

$31+14.76+17+8.35$

$-4+7-10+5-\left(-3\right)$

$\frac{\left(x-4\right)\left(x-2\right)^2}{\left(x-3\right)^2}=0$

$-6\left(3w+1\right)+-3\left(4w-2\right)$