$5x^2+2x-3=0$
$y'\:+2ty=3t$
$\frac{x+2}{x^2+4x+4}:\frac{x^2-4}{x^3+8}$
$y=\ln\left(8x\right)$
$2\frac{dy}{dx}=xy\left(x+1\right)$
$4\sin\left(4x\right)\cot\left(4x\right)$
$\int_2^{xy}\left(24xy\right)dz$
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