$\frac{d}{dx}\left(\frac{1}{2+x}\right)$

$\frac{6}{\left(2x+1\right)^2}$

$\frac{\tan\left(u\right)\cot\left(u\right)}{\sec\left(u\right)}$

$\int_0^2\left(\frac{1}{\sqrt[2]{2x-x^2}}\right)dx$

$x\cdot\frac{dy}{dx}+4\cdot y=x\cdot ln\left(x\right)$

$f\left(x\right)=9x^3+6x$

$\int tg^6xdx$