$\left(r-3\right)^4$
$xy^2=12$
$-8m^4-2m^4$
$\left(\sec\left(a\right)-1\right)\left(\sec\left(a\right)+1\right)$
$\sqrt{20x^{10}z^{11}}$
$\int_1^{\infty}\left(\frac{n+5}{n^2}\right)dx$
$\left(3xy^2z^5+2\right)\left(2+8xy^2z^5\right)$
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