$a^2b^4-c^2$
$x^2+\frac{2}{3}x=0$
$-5+\left(-18\right)+\left(-19\right)+\left(-13\right)$
$\frac{dy}{dx}=-\frac{5xy^3}{2}+5y$
$2x\:+\:6\:\ge\:20$
$f\left(a\right)=3a-a^2$
$2\:\left(-8\:+\:3b\right)$
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