$144y^2-16^2$
$xy=-1$
$\frac{4}{5}-x^2.8x^3-5x+3$
$\frac{\left(x^2+19x-47\right)}{\left(4x^2+2x+18\right)}$
$\lim_{x\to\infty}\left(15x^2-15x^4\right)$
$\cos^2x-\cos x=2$
$\sqrt[5]{x^2}-\frac{1}{4\sqrt[5]{x^3}}+\frac{1}{64\sqrt[5]{x^3}}$
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