$x^2+1,78\cdot10-5\:-7,12\cdot10-6$
$\frac{1}{\sin}+\frac{1}{\tan}$
$\left(\left(3y\right)\left(b\right)\right)^5$
$\int\left(1+15x^2\right)^{-1}dx$
$\left(2y+y^2\right)^3$
$0x^2-2x^3$
$\left(4xy+3y\right)dx+y^2dy=0$
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