$\int_0^2-22xdx$

$\left(m^3-n^3\right)\cdot\left(m^3+n^3\right)$

$\left(-8\right)-\left(-3\right)$

$\sec\left(16.363636\right)$

$\frac{d}{dx}\left(\left(\left(x-2\right)\left(x+3\right)^3\right)\left(x^2-1\right)^4\right)$

$\sqrt{0.004464999999999999}$

$\frac{\left(-5\right)+\left(-7\right)}{-4}$