$\left(3y+4z\right)\left(3y-4z\right)$
$9m^2-25n^2$
$\left(\frac{1}{6}x^3-\frac{3}{2}x^2y^3\right)^3$
$\frac{dy}{dx}=5y\left(6-y\right)$
$\frac{-x^5-3x^2-x^2+1}{-x^2+2x+1}$
$\left(3xy^2-y\right)^3$
$\int\left(\log x^2\right)dx$
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