$\frac{dy}{dx}=\frac{5\left(y^2+3y+2\right)}{x\left(5y+7\right)}$
$-x+2\ge-1$
$\lim_{x\to0}\left(\frac{\tan^5\left(2x\right)}{x.\sin^3\left(3x\right)}\right)$
$\int3t^2dt$
$\left(9\right)\left(-4\right)\left(6\right)$
$x^2-4x-6=0$
$\left(3x+5y\right)\left(3x^2-xy+4y^2\right)$
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