$\frac{14^9.15^4.30^2}{80^3.35^3.21^6}$
$y'=\frac{x-1}{y^2\:},\:y\left(0\right)=2$
$\left(8-x^3\right)^2$
$\int_{-2}^0\left(3x\right)dx$
$\frac{48}{2x}$
$-8\:.\:2\::\:\left(+4\right)$
$\int\frac{3x^3+4x^2-5x+7}{x^2\left(5x-5\right)^2}dx$
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