$f\left(x\right)=\left(\frac{-20x+4}{ax+10}\right)$
$\int\frac{1}{\left(x^2+5x+6\right)}dx$
$-34^2+-3^24^2-10-3^24$
$4.6\cdot\left(-9\right)$
$15x^4+5x^2y-10y^2$
$\left[\frac{\left(-49\right)}{7}\right]\cdot\left[\frac{12}{\left(-4\right)}\right]$
$x^2+9-x^2-9$
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