$\left(13a+12b^2-c-8\right)+\left(a+3b^2+6c+10\right)$
$\int\left(x^2+3\right)ln\left(2x\right)dx$
$-5.4+9$
$\int_1^e\frac{2\ln^3\left(x\right)}{x}dx$
$\int\left(\frac{1+4x-7x^2}{x^2}\right)dx$
$-6\cdot73$
$\frac{8x^4-6x^3+10x^2-2}{x^2+1}$
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