$2x+\sqrt{x+6}=2$
$4\cdot157$
$\int\frac{x-1}{\left(x^3+4x^2+4x\right)^2}dx$
$\lim_{x\to0}\left(\frac{1-6\left(x\right)}{x^2}\right)$
$-3x^2+y\left(4x-1\right)+1$
$\frac{d}{dx}e^{4x+1}$
$\left(3a^3\:-\:3b^2\right)\left(3a^2\:+\:3b^2\right)$
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