$\lim_{b\to3}\left(\frac{b^3-27}{b-3}\right)$
$\lim_{x\to1}\left(\frac{x^3-2x-11}{x+3}\right)$
$\frac{sec\left(x\right)}{sec\left(x\right)-tan\left(x\right)}=sec\left(x\right)\left(sec\left(x\right)+tan\left(x\right)\right)$
$\left(8b\:+\:10\right)$
$3x<4-x$
$x^4+18x^2+81=0$
$4^2:4^{-2}$
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