$\left(-1\right)\left(-1\right)\left(-1\right)\left(-5\right)$
$\frac{x}{4}+8=6$
$\lim_{x\to-\infty}\left(\frac{2x^3+x^2+3}{x+1}\right)$
$\int\frac{10x^6-4x^2-15x+16}{x}dx$
$x+5=-14$
$\sqrt[4]{81x^5}5^8$
$\int x\left(x+1\right)\frac{1}{3}dx$
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