$-8-\left(3+5+6\right)+2$
$\frac{n}{4}+1=5$
$\left(t\right)=b\left(a-e-bt\right)$
$a-3\ge2$
$\left(-1\right)^3-2\left(-1\right)^2-3\left(-1\right)+1$
$\left(8x+5\right)^3$
$4+a=13$
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