$\frac{1}{4}-\frac{z}{3}+\frac{z^2}{9}$
$\frac{10\sqrt{20}}{\sqrt{2}}$
$-2-\frac{-16}{4}$
$\frac{d}{dx}\left(sin^4x\right)\sqrt{6x+1}$
$49z^2-36$
$x+3=x-3$
$\int\cos^{19}\theta\:\sin\theta\:d\theta\:$
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