$\lim_{x\to0}\left(\frac{4-4\cos\theta}{\sin3\theta}\right)$
$\left(m-9\right)\left(m+9\right)$
$\left(5x+3\right)+3x-2$
$\sin\left(4x\right)+\sin\left(2x\right)+\sin\left(3x\right)$
$12\cdot7$
$x^2-2x+1=9$
$1.78\:x\:1.78$
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