$\left(-24\right)+\left(-8\right)-\left(-6\right)$
$\int\left(\frac{12x}{\left(2x^2+3\right)^3}\right)dx$
$x^2+9<3$
$\int\sec^6\left(\frac{x}{2}\right)dx$
$6+6\left(3^2-2\right)+3^2-2\left(5+6\right)$
$\left(3x\:-\:5y\right)^3$
$x-2y-4,x=8,y=2$
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