$\frac{3}{4}x+4=22$
$\left(16x^2-7x-8\right)\left(-6x^2-3x+6\right)$
$\lim_{x\to0}\left(1+x\right)^{\frac{1}{2x+1}}$
$4a-5a$
$-16sin\left(x\right)=0$
$\ln\left(6-x\right)+\ln\left(-5-x\right)=\ln\left(3-9x\right)$
$-z^2+2z-1$
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