$\lim_{x\to-1}2\pi$
$\frac{yx^3}{3y^4}$
$\left(xy-6z\right)\cdot\left(xy+6z\right)$
$3x^2-4x+4=0$
$\frac{x^3-4x^2-4x+16}{x-4}$
$f\left(x\right)=\frac{19x^{2}+25x+21}{3x\left(x+1\right)^{2}}$
$\lim_{x\to+\infty}\left(1+2x+\frac{2x^3}{\sqrt{x^4-13x^2+36}}\right)$
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