$\left(4m+6\right)\left(4m-9\right)$
$\frac{3x^3+2x-1}{x+2}$
$x^2-4y^2$
$\left(+12\right)-\left(-3\right)+\left(-1\right)$
$\left(5x-1\right)^2-\left(3x+1\right)^2$
$\frac{sin\left(x\right)}{1-cos\left(x\right)}=\frac{1}{sin\left(x\right)}+\frac{1}{tan\left(x\right)}$
$\lim_{x\to2}\left(\frac{x^4+3x^3\:-10x^2}{x^2-2x}\right)$
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