$\left(3a+5\right)\left(ma+2\right)$
$18+x^2-6x=0$
$\lim_{x,y\to0,ln2}\left(e^{x-y}\right)$
$-\frac{1}{2}\cdot16$
$1\:x\:-5$
$\left[\sqrt[2^{18}]{\left[\left(x^4\right)^{64^2}\right]^8}.x^{16^4}\right]^{\frac{4}{3}}$
$\left(-3\right)^3-4\left(2\right)$
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