$\int\:\frac{3x}{\sqrt{x\:+\:8}}dx$
$8-7x=-10x-4$
$\left(\frac{1}{2m^2+5}\right)\left(\frac{1}{2m^2+7}\right)$
$\sqrt{c^4}$
$sec\left(\frac{\pi}{2}-x\right)=\:cscx$
$-\frac{1}{2}\left(\sin^2\left(x\right)+\sin^2\left(y\right)\right)$
$x^2-4x+18=0$
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