$\int\frac{\theta\:^3+5\theta\:}{\left(\theta\:^2+1\right)^2}dx$
$xy=4y$
$4x^2-2x-23$
$8u-9u$
$\frac{6p^3q^2}{4pq^{-2}}$
$\left(-23m-10n+15p-18r-1\right)-\left(-15m+20p-30p+21r-12\right)$
$\lim_{x\to\infty}\left(\frac{x^3h+3xh^2+h^3}{2xh+5h^2}\right)$
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