$\left(2x+3\right)^2-\left(4y-5\right)^2$
$5x^4y+20x^3y+20x^2y$
$\frac{x+3}{3}+4=\frac{x+9}{2}$
$\lim\:_{x\to\:\infty\:}\left(1-\frac{4}{x}\right)^{2x}$
$5\left(x\:-\:3\right)\:=\:10$
$8x-3>7x+12$
$\int\:\frac{-x^2+24x-20}{x^3-4x}dx$
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