$x^2+4x+3=5$

$\left(\left(-2\right)^3\right)^4\cdot\left(2^2\right)^3\cdot\left(\left(-3\right)^4\right)^3$

$\frac{4}{7}m^4\cdot8$

$\lim_{x\to\infty}\:-1^n-1$

$\int t^2\left(8t+7\right)dt$

$y=\ln\left(\frac{\left(a^2-x^2\right)^{\frac{1}{2}}}{x}\right)$

$-10+10\cdot10$