$\left(\frac{1}{4}x+\frac{2}{3}x\right)^2$
$\lim_{x\to\infty}\frac{9x^5+3x^2}{4-x^2}$
$x-2y-2\left(x+2y\right)+5y\:\:$
$f\left(x\right)=x^3\left(1\right)+1$
$\frac{4x^2-16}{x-2}$
$\left(-2k-11\right)^2$
$\left(x\:-\:5\:\right)\left(x+6\right)$
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