$-x\left(3\right)+3x-1,8=0$
$\frac{0}{\frac{1}{2}}$
$5-\frac{2}{x^4}$
$x^2+3x=1$
$x^2+9x=16$
$\frac{61+69}{2}$
$\frac{2x^3+x-6}{x+2}$
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