$\int\frac{6x^3}{x^2-4}dx$
$\cos\left(\frac{180}{7}\right)+\cos\left(\frac{540}{7}\right)-\cos\left(\frac{360}{7}\right)$
$\frac{3x}{x+1}=\frac{12}{x^2-1}+2$
$8a^3-5a^3$
$-7y^2-6y+9-8y^2$
$\sqrt{x-4=12}$
$\frac{dy}{dx}=3x+2$
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