$\left(2a^2+7a+1\right)^2$
$g\left(x\right)=\frac{x-1}{4\left(1\right)^{2}+5x-14}$
$\frac{dn}{dt}=0.25n\left(10-n\right)$
$\sin\left(x\right)^2\cdot\sec\left(x\right)^2=\tan\left(x\right)^2$
$\int6x\cdot\ln\left(3x\right)dx$
$\frac{m^{12}-n^{18}}{m-n}$
$3x^2+4x-9$
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