$\frac{dy}{dx}=\frac{xe^x}{3y^2}$
$x^2+2x+0$
$-2a-9=39$
$\int x\cdot\ln\left(\frac{2}{x^2}\right)dx$
$\frac{x^3+2x+1}{x^2-x+3}$
$3y^3dx-6xdy=0$
$\frac{11.9}{98.1}$
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