$\frac{dx}{dt}=\frac{5x}{t}+t$
$sin^2\theta\:\left(1+tan^2\theta\:\right)=tan^2\theta\:$
$x^2+3xy+y^2-x^2\frac{dy}{dx}=0$
$\left(\frac{4x^2+6x^3}{x^2-2x}\right)^{-2}$
$13x^2y^32$
$\frac{dy}{dx}x^2-y^3=0$
$x^2-10x\le-25$
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