$\left(x+6\right)\left(x+2\right)+\left(x+4\right)\left(x+1\right)-2x^2$
$\left(1-x^3y^{-2}\right)^3$
$x^2+7x=8$
$x\frac{dy}{dx}-y=x^2\sin\left(3x\right)$
$ab-ac^2$
$x^2+\frac{3}{4}x=0$
$\frac{\left(8^4\right)^2}{8^{11}}$
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