$4x-8<8$

$24a^2+12a^2$

$4x^2\cdot4x+4$

$\int\left(\frac{7}{x^8}\right)dx$

$\left(x\right)^{-\frac{1}{2}}\cdot\left(\left(x+x^3\right)^{\frac{1}{2}}-\left(x+1+\left(x+1\right)^3\right)^{\frac{1}{2}}\right)$

$\int\left(\frac{z^2}{5z^3+8}\right)dz$

$4xy-2x^2y=2\left(x-xy\right)$